Question

A trianglar carpet is laid in a square room of side 12m, if the base of the carpet is 10m and the height is 8m, calculate the area of the floor uncoverd​

Answer 1

◈ Area of square room :

`:\implies\sf\:A_s=(side)^2`

`:\implies\sf\:A_s=(12)^2`

`:\implies\bf\:A_s=144\:m^2`

◈ Area of triangular carpet :

`:\implies\sf\:A_t=(1)/(2)* base* perpendicular`

`:\implies\sf\:A_t=(1)/(2)* 10* 8`

`\:\implies\sf\:A_t=(1)/(2)* 80`

`:\implies\bf\:A_t=40\:m^2`

◈ Uncovered area of room :

`:\implies\sf\:\Delta A=A_s-A_t`

`:\implies\sf\:\Delta A=144-40`

`:\implies\:\boxed{\bf{\blue{\Delta A=104\:m^2}}}`