Tim's bean sprout grew 3/ inches. Teegan's bean sprout grew 2 3/4 inches. How many more inches did Tim's bean sprout grow than Teegan's? First, estimate the …

Question

asked Oct 5, 2021 131k views

1 Answer

Andrewsi · Answer 1 · 2021-10-09T10:55:21+0000

Answer:

Tim's bean sprout grow by more than
$(5)/(8) \text{ inches}$ .

Explanation:

We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.

We have to find how many more inches did Tim's bean sprout grow than Teegan's.

Firstly, converting both the mixed fractions in improper fraction get;

Tim's bean sprout grew =
3(3)/(8) =
$(27)/(8) \text{ inches}$

Teegan's bean sprout grew =
2(3)/(4) =
$(11)/(4) \text{ inches}$

Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.

Tim's bean sprout grew =
$(27* 1)/(8* 1) = (27)/(8) \text{ inches}$

Teegan's bean sprout grew =
$(11 * 2)/(4* 2)=(22)/(8) \text{ inches}$

Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.

So, Tim's bean sprout grow by more than =
(27)/(8)- (22)/(8) =
$(5)/(8) \text{ inches}$

Hence, Tim's bean sprout grow by more than
$(5)/(8) \text{ inches}$ .