asked 80.9k views
9 votes
Describe how crystsls of copper(11) sulphate can be prepared from the mixture of excess copper(11) oxide and copper(ii) sulphate solution obtained when the reaction stops

1 Answer

11 votes

Steps:

1) place some sulfuric acid in a beaker and warm it in a water bath.

2) add a spatula of copper(II) oxide powder to the acid and stir with a glass rod.

3) continue adding copper(II) oxide powder until it is in excess.

4) filter the mixture to remove the excess copper(II) oxide.

5) pour the filtrate (the copper(II) sulfate solution) into an evaporating basin.

6) heat the copper(II) sulfate solution to evaporate half the water.

7) pour the solution into an evaporating basin and leave to allow all the water to evaporate.

Results:

Record the appearance of the copper(II) sulfate crystals, including their colour and shape.

Analysis:

Hydrated copper(II) sulfate crystals should be blue and regularly shaped. Describe how your crystals compare to this description.

answered
User Hiroprotagonist
by
8.4k points
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