Write the equation for the line that passes through (-5, -4) and (3, 12)

Question

asked Nov 19, 2021 52.0k views

2 Answers

Joseph Adams · Answer 1 · 2021-11-23T08:19:08+0000

Answer:

$y=2\,x+6$

Explanation:

Start by finding the slope of the segment that joins the two given points, using the slope formula:

slope=(y_2-y_1)/(x_2-x_1) =(12-(-4))/(3-(-5)) =(16)/(8) =2

Now, you can write the general equation of the line in slope-intercept form as:

$y=m\,x+b\\y=2\,x+b$

and find the line's y-intercept (b) by using either one of the given points - for example (3, 12):

$y=2\,x+b\\12=2\,(3)+b\\12=6+b\\b=6$

Therefore, the equation of the line is:

$y=2\,x+6$