Question

A crowbar of 2m is used to lift an object of 800N. If the effort is 160m, calculate the effort applied.

Plz give full process answer. I want it soon. ​

Answer 1

It's of science not of mathematics

Answer 2

`\boxed{ \bold{ \huge{ \boxed{ \sf{10 \: N}}}}}`

Explanation:

Given,

Load distance ( LD ) = 2m

Load ( L ) = 800 N

Effort distance ( ED ) = 160 m

Effort ( E ) = ?

Finding the Effort applied

Apply the principal of simple machine :

`\boxed{ \sf{L * LD = E* ED}}`

`\longrightarrow{ \sf{800 * 2 = E * 160}}`

`\longrightarrow{ \sf{1600 = 160 \: E}}`

`\longrightarrow{ \sf{160E = 1600}}`

`\longrightarrow{ \sf{ (160E)/(160) = (1600)/(160) }}`

`\longrightarrow{ \sf{E = 10 \: \: newton}}`

Effort applied = 10 N

Hope I helped!

Best regards! :D