Question

Please help me with this question It’s due is in 5 min plzzz help I will beg ur legs

Answer 1

`(s)/(2t)`

Explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

`a^(x) *a^(y) = a^(x + y)`

So let's group like terms in the numerator:

`4r^(3) r^(-5) s^(-2) s^(-1)t` We can add terms like in the example.

`4 r^(-2) s^(-3) t`

Let's rearrange the denominator.

`8r^(-2) s^(-4) t^(2)`

Now we have:

`(4r^(-2) s^(-3)t)/(8 r^(-2) s^(-4) t^(2) )` Cancel like terms

4/8 = 1/2

`r^(-2) /r^(-2)` = 1 So it cancels

`s^(-3) / s^(-4) = s^(-1)` = s Since s is raised to the -1 it goes on top and becomes s.

`t / t^(2) = 1/t`

Now we combine everything back together:

`(s)/(2t)`