Question

Find the equation of the line parallel to y= -5x-3 that passes through the point ( -5, -4). If possible, write the equation in slope-intercept form.

Answer 1

y = -5x - 29

Explanation:

y-intercept form is y = mx +b,

m is slope, for parallel line slope is the same, so m= -5

y = -5x + b

To find b, we need to use the point (-5, - 4).

- 4 = -5*(-5) + b

- 4 = 25 + b

b = - 29

y = -5x - 29