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What is the equation of the line through 4.2 and 0, -2?

What is the equation of the line through 4.2 and 0, -2?-example-1

1 Answer

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Answer:

y = x-2

Explanation:

y = mx + b as an equation

m = slope

slope = (change in y) / (change in x) = (y₂-y₁)/(x₂-x₁) = (y₁-y₂)/(x₁-x₂) = (2-(-2))/(4-0) = 4/4 = 1

y = 1*x + b

plug a value in, e.g. (0, -2)

-2 = 1 * 0 + b

-2 = b

our equation is thus

y = x - 2

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User Stvn
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