Question

SA= 2 pie r square + 2 pie rh, solve for h please ​

Answer 1

`\huge \boxed{h= \displaystyle (SA)/(2\pi r) -r}`

`\rule[225]{225}{2}`

Explanation:

`SA=2\pi r^2 +2\pi rh`

Subtracting
`2\pi r^2` from both sides:

`SA-2\pi r^2 =2\pi rh`

Dividing both sides by
`2\pi r`:

`\displaystyle (SA-2\pi r^2)/(2\pi r) =h`

Simplifying the equation:

`\displaystyle (SA)/(2\pi r) -r=h`

`\rule[225]{225}{2}`