Question

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Answer 1

`\textsf{If }\: X \sim\textsf{N}(\mu,\sigma^2)\:\textsf{ then }\: (X-\mu)/(\sigma)=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)`

Therefore,

`\textsf{If }\: X \sim \textsf{N}(33,4^2)\:\textsf{ then }\: (X-33)/(4)=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)`

`X=29 \implies Z=(29-33)/(4) \implies Z= -1`

`X=41 \implies Z=(41-33)/(4) \implies Z=2`

`X=25 \implies Z=(25-33)/(4) \implies Z=-2`

No given lifespan is unusual, as they are all within 3 standard deviations of the mean.