Question

What is the mass of 3.95 l of methane gas at 0.870 atm and 35.0 degrees celsius?

Answer 1

2.174 gm

Step-by-step explanation:

PV = nRT n = number of moles

R = gas constant = .082057 L-atm/(K-mol)

T must be in units of K

.870 (3.95) = n (.082057)(35+273.15)

solve for n = .1359 moles

Methane mole weight (CH4) = 16 gm / mole

.1359 moles * 16 gm/mole = 2.174 gm