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5 votes
Find an equation of the line parallel to y=x+3 and that passes through the point (1 -5)

asked
User Hashier
by
7.8k points

2 Answers

1 vote

Answer:

y=x-6

Step-by-step explanation:

Y=x+3 according to this equation, the gradient is 1 comparing to y=mx+c. so m is the gradient. so from the equation, the coefficient of x is 1. since the line is parallel so it means the new equation has the same gradient m.

y=x+c but it passes through 1,-5...when x= 1, y=-5 from here , we Can find the new intercept c. -5=1+c. so c=-5-1=-6

the new equation y=x-6

6 votes
Answer: y = x - 6

Step-by-step explanation:

It needs to have the same slope so that it parallel.

answered
User Lifebalance
by
7.9k points

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