Question

If the 11th of a geometric sequence is 32 times larger than the 6th term, then what is the common ratio of the sequence?

Answer 1

2

Explanation:

Hello, let's note
`(a_n)` this sequence and r the ratio, we can write

`a_n=a_0r^n`

With
`a_0` different from 0 and then

`a_(11)=32a_6<=>a_or^(11)=32a_0r^6<=>r^(11-6)=32=2^5<=>r^5=2^5<=>r=2`

Thanks