Question

Find sin60 A.1/2 B.2/2 C.3/2

Answer 1

`\huge\boxed{\sin60^o=(\sqrt3)/(2)}`

Explanation:

Let's take a right triangle with acute angles 30° and 60°.

We know that the ratio of the sides of such a triangle is 2 : 1 : √3

(look at the picture)

We know:

`sine=(opposite)/(hypotenuse)`

In this triangle we have:

`opposite=a\sqrt3\\hypotenuse=2a`

Substitute:

`\sin60^o=(a\sqrt3)/(2a)` cancel a

`\sin60^o=(\sqrt3)/(2)`

Answer 2

Answer:
`(√(3) )/(2)`

Explanation:

To find sin(60), you need to know the unit circle. Sin(60) is the same as sin(π/3). On the unit circle, sin(π/3) is √3/2. We know this because the coordinates are (cos, sin). Sin is the y coordinate.