Question

What is an equation of a line that passes through the point of (-8 2) and (-4,-3)

Answer 1

y = -5/4x -8

Explanation:

`(-8,2)=(x_1 ,y_1)\\(-4 ,-3) = (x_2 ,y_2)\\\\(y-y_1)/(x-x_1) = (y_2-y_1)/(x_2-x_1)\\ \\(y-2)/(x-(-8))= (-3-2)/(-4-(-8))\\ \\(y-2)/(x+8)= (-5)/(-4+8) \\ \\\\(y-2)/(x+8) = (-5)/(4)\\ \\Cross\:Multiply \\4(y-2) = -5(x+8)\\\\4y-8 =- 5x-40\\\\4y = -5x-40+8\\\\4y =- 5x-32\\\\(4y)/(4) = (-5x)/(4) + (-32)/(4) \\\\y = -(5)/(4)x-8`