Question

You have a container filled with 24 moles of neutral lithium. How much negative electric charge is contained in the electrons of all the lithium atoms in the container

Answer 1

In a container filled with 24 moles of neutral lithium, the total negative electric charge contained in the electrons of all the lithium atoms is -6.95 × 10⁶ C.

Step-by-step explanation:

Lithium (Li) has an atomic number of 3, meaning that in a neutral atom, the number of electrons is also 3. Therefore, in a container filled with 24 moles of neutral lithium, the total number of electrons would be 3 times the Avogadro's number (6.022 × 10²³) multiplied by the number of moles. This can be calculated as:

Total number of electrons = 3 * Avogadro's number * number of moles

Total number of electrons = 3 * (6.022 × 10²³) * 24

Total number of electrons = 4.334 × 10²⁵

Since each electron carries a negative charge of -1.602 × 10⁻¹⁹ coulombs, the negative electric charge contained in the electrons of all the lithium atoms in the container can be calculated as:

Total negative electric charge = Total number of electrons * charge per electron

Total negative electric charge = (4.334 × 10²⁵) * (-1.602 × 10⁻¹⁹)

Total negative electric charge = -6.95 × 10⁶ C

Answer 2

There are 6.94x10⁶ C of the negative electric charge contained in the electrons of all the lithium atoms in the container.

Step-by-step explanation:

We have 3 moles of electrons (e⁻) in 1 mol of Li, so the quantity of negative electric charge is:

`(3 moles \thinspace e^(-))/(1 mol Li)*24 moles Li*(6.022 \cdot 10^(23) e^(-))/(1 mol \thinspace e^(-))*(1.60 \cdot 10^(-19) C)/(1 e^(-)) = 6.94 \cdot 10^(6) C`

Therefore, there are 6.94x10⁶ C of the negative electric charge contained in the electrons of all the lithium atoms in the container.

I hope it helps you!