asked 31.8k views
18 votes
If f(x)= 2^8-x+3, what is the value of f(5), to the nearest tenth (if necessary)

1 Answer

8 votes

Answer:

Explanation:

f(5) = 2^8 - 5 +3

f(5) = 256-5+3

f(5) = 254

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User Eric Smalling
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