Question

The functions q and r are defined as follows

g(x) = -2x-2
r(x) = x² – 2
Find the value of r(q(4)).
r(9 (4)) =

Answer 1

Explanation:

Answer 2

98

Explanation:

So we have the two functions:

`g(x)=-2x-2\text{ and } r(x)=x^2-2`

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

`g(x)=-2x-2\\g(4)=-2(4)-2\\`

Multiply:

`g(4)=(-8)-2`

Subtract:

`g(4)=-10`

Now, substitute this into r(g(4)):

`r(g(4))\\=r(-10)`

And substitute this value into r(x):

`r(-10)=(-10)^2-2`

Square:

`r(-10)=100-2`

Subtract:

`r(-10)=98`

Therefore:

`r(-10)=r(g(4))=98`