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5 times the sum of the digits of a two digit number is 9 less than the number formed by reversing its digits. If 4 times the value of the digit at ones place is equal to the half of the place value of the digit at tens place, find out the number. ​

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Answer:

5 times the sum of the digits of the number is 9 less than the number formed by reversing digits. → x = (5y - 9)/4 -- equation (1). Case - 2 : And, 4 times the value of the digits at ones place is equal to half the place value of digit at tens place (10x/2).

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User Michelpm
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