Question

Please help me with this #9

Answer 1

`\text{First term,} ~ a = 5\\\\\text{Common ratio,}~ r = \frac{10}5 = 2\\\\\text{Nth term} = ar^(n-1) = 5\cdot2^(n-1)\\\\\text{4th term } = 5\cdot 2^(4-1) = 5 \cdot 2^3 = 40\\\\\text{5th term} = 5 \cdot 2^(5-1) = 5 \cdot 2^4 = 80\\\\\text{Hence the next two terms are 40 and 80.}`