Question

How many electrons would have to be removed from a coin to leave it with a charge of +1.0 10-7 C?

Answer 1

`n=6.25* 10^(11)`

Step-by-step explanation:

We need to find the number of electrons that would have to be removed from a coin to leave it with a charge of
`+10^(-7)\ C`. Then the number of electrons be n. Using quantization of electric charge as :

q = ne

e is charge on an electron

`n=(q)/(e)\\\\n=(10^(-7))/(1.6* 10^(-19))\\\\n=6.25* 10^(11)`

So, the number of electrons are
`6.25* 10^(11)`.