PLEASEEEEEE Which system of equations does not have a real solution? y = x 2 + 3 x - 5 and 4 x + 5y = 20 y = x 2 + 3 x - 5 and x + y = -10 y = x 2+ 3 x- 5 and x + y = -9

Question

asked Jun 25, 2021 98.4k views

2 Answers

Lely · Answer 1 · 2021-06-30T20:09:32+0000

Answer:

$\Large \boxed{y = x^2 + 3 x - 5 \ \ \mathrm{and} \ \ x + y = -10}$

Explanation:

y = x² + 3 x - 5 and x + y = -10 are the system of equations that do not have a real solution.

When the two equations are graphed and if they do not intersect, then there are no real solutions for the system of equations.