Question

In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

Answer 1

Answer: 6π

Explanation:

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

`A=\pi r^2\bigg((\theta)/(360^o)\bigg)`

Given: r = 6, Ф = 60°

`A=\pi (6)^2\bigg((60^o)/(360^o)\bigg)\\\\\\.\quad =\pi (6)^2\bigg((1)/(6)\bigg)\\\\\\.\quad =6\pi`