Question

Find a vector 6 unit long in the direction of A = 2i + 2j – 1k​

Answer 1

B=4i+4j-2k

Explanation:

Lets find the length of vector A

IAI= sqrt(2²+2²+1²)=sqrt(9)=3

So B=2*A = 2(2i+2j-1k)=4i+4j-2k