Question

I tried different ways of doing the equation but I still didn't get a correct answer ​

Answer 1

`\huge \boxed{\mathrm{0.65 \ in^2}}`

Explanation:

Area of square =
`s^2`

`0.5^2 = 0.25`

Area of triangle =
`(bh)/(2)`

`(0.5 * 0.4)/(2)=0.1`

The surface area of the net = area of square + 4(area of triangle)

`0.25+4(0.1)=0.65`