Question

(20pts)prove that the difference of the squares of two consecutive integers is equal to the sum of the integers, whenever the larger of the two integers comes first​

Answer 1

see below (I hope this helps!)

Explanation:

If the two numbers are x and x + 1, then:

(x + 1)² - x²

= x² + 2x + 1 - x²

= 2x + 1

= x + (x + 1)