Question

Two rectangles have equal areas. If the base and altitude of one are 12mm and 8mm, and the base of the other is 16mm, what is the altitude of the second rectangle?​

Answer 1

6mm

Logic


R1a • R1b=R2a • R2b

R1a=12
R1b=8
R2a=16
R2b=x

12•8=96

96=16•x

96/16=x

x=6

R2b=6

Answer 2

6mm

Explanation:

since the area of both rectangle is equal, therefore :

Arectangle 1= Arectangle 2

base 1*altitude 1 =base 2*altitude 2

12mm*8mm = 16mm* altitude 2

96mm²= 16mm* altitude 2

96mm²/16mm = altitude 2

6mm = altitude 2