Question

Find the length of a line segment whose endpoints are (-2,3) and (6,3)

Answer 1

The length would be eight bc -1 -2 0 1 2 3 4 5 6

Answer 2

8

Explanation:

Since we want to find the length of a line segment, we can use the distance formula.

`d=\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1) )^2 }`

(x₁, y₁) and (x₂, y₂) are the points given.

The points we are given are: (-2,3) and (6,3). Therefore,

`\\x_(1) =-2\\y_(1)=3 \\x_(2) = 6\\y_(2) =3`

Plug each value into the formula.

`d=\sqrt{{(6--2})^2+(3-3 )^2} }`

Evaluate inside of the parentheses first.

`d=√((6+2)^2+(0)^2)`

`d= √((8)^2+(0)^2 )`

Evaluate the exponents.

8²= 8*8=64

`d=√(64+(0)^2)`

0²= 0*0= 0

`d=√(64+0)`

Add 64 and 0.

`d=√(64)`

Take the square root of 64.

`d= 8`

The length of the line segment is 8