Question

In this diagram, bac~edf. if the area of bac= 6 in.², what is the area of edf? PLZ HELP PLZ PLZ PLZ PLZ

Answer 1

Area of ΔEDF = 2.7 in²

Explanation:

It's given in the question,

ΔBAC ~ ΔEDF

In these similar triangles,

Scale factor of the sides =
`\frac{\text{Measure of one side of triangle BAC}}{\text{Measure of one side of triangle EDF}}`

`=\frac{\text{BC}}{\text{EF}}`

`=(3)/(2)`

Area scale factor = (Scale factor of the sides)²

`\frac{\text{Area of triangle BAC}}{\text{Area of triangle EDF}}=((3)/(2))^2`

`\frac{6}{\text{Area of triangle EDF}}=((9)/(4))`

Area of ΔEDF =
`(6* 4)/(9)`

= 2.67

≈ 2.7 in²

Therefore, area of the ΔEDF is 2.7 in²