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(x^2-4x)^2+7x^2-28x+12=0

(x^2-4x)^2+7x^2-28x+12=0
asked 188k views
3 votes
(x^2-4x)^2+7x^2-28x+12=0

asked
User Andrea Carraro
by
8.3k points

1 Answer

5 votes

Answer:


x^4-9x^2-28x=-12

Explanation:


(x^2-4x)^2+7x^2-28x+12=0


(x^4-16x^2)+7x^2-28x=-12


x^4-9x^2-28x=-12

answered
User Grechut
by
8.2k points
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