A club has 16 members, included Mary and Peter. If two representative are randomly selected from those members, find the probability that (d) Mary or Peter is chosen.

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asked Oct 8, 2021 234k views

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Geejay · Answer 1 · 2021-10-14T11:34:37+0000

Answer:

12.5 percent; 2/16; 1/8

Explanation:

Peter and Mary make up 2 of the clubs members, so the probability that they are chosen is 2/16. This simplifies to 1/8, and in decimal form is .125. Therefore, the percentage form of the probability they are chosen is 12.5 percent.

A club has 16 members, included Mary and Peter. If two representative are randomly selected from those members, find the probability that (d) Mary or Peter is chosen.

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A club has 16 members, included Mary and Peter. If two representative are randomly selected from those members, find the probability that (d) Mary or Peter is chosen.​

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A club has 16 members, included Mary and Peter. If two representative are randomly selected from those members, find the probability that (d) Mary or Peter is chosen.