Question

If the weight (in grams) of cereal in a box of Lucky Charms is N(470,5), what is the probability that the box will contain less than the advertised weight of 453 g?

Answer 1

The probability that the box will contain less than the advertised weight of 453 g is 0.00034.

Explanation:

Let X represent the weight (in grams) of cereal in a box of Lucky Charms.

It is provided that X follows a Normal distribution with parameters, μ = 470 and σ = 5.

Compute the probability that the box will contain less than the advertised weight of 453 g as follows:

`P(X<453)=P((X-\mu)/(\sigma)<(453-470)/(5))`

`=P(Z<-3.4)\\=0.00034`

*Use the z-table.

Thus, the probability that the box will contain less than the advertised weight of 453 g is 0.00034.