Question

What are the vertical asymptotes of the function above?

1) x= -1 and x = -2
2) x= -1 and x = 2
3) x= 1 and x = -2
4) x = 1 and x = 2

Answer 1

third option

Explanation:

Given

f(x) =
`(5x+5)/(x^2+x-2)`

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

solve x² + x - 2 = 0 ← in standard form

(x + 2)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 1 = 0 ⇒ x = 1

The vertical asymptotes are x = 1 and x = - 2