Question

When HCl is added to water, the [H3O+] = 0.6 M. What is the [OH-]?

What is the pH of the solution?

Answer 1

pH=0.22.

`[OH^-]=1.66x10^(-14)M`

Step-by-step explanation:

Hello,

In this case, since the pH is directly computed from the given concentration of hydronium ions:

`pH=-log([H_3O^+])=-log(0.6M)=0.22`

It is widely known that the pH and POH are directly related via:

`pH+pOH=14`

Therefore, the pOH is:

`pOH=14-pH\\\\pOH=14-0.22=13.78`

Thus, the concentration of hydroxyl ions are computed from the pOH:

`pOH=-log([OH^-]}\\\\`

`[OH^-]=10^{-pOH]=10^(-13.78)`

`[OH^-]=1.66x10^(-14)M`

Regards.