asked 9.7k views
5 votes
Let $x=5$, $y=\frac{3}{4}$, and $z=-\frac{1}{7}$. What is $$\frac{xz}{y}?$$

asked
User Redhead
by
7.9k points

1 Answer

5 votes

Answer:

-20/21

Explanation:

Given x = 5, y = 3/4 and z = -1/7, 2=we are to calculate
(xz)/(y). Substituting the value of x, y and z into the expression will give;


= (xz)/(y)\\\\ (5(-1/7))/(3/4) \\= (-5/7)/(3/4)\\\\= (-5)/(7) * (4)/(3)\\ \\ = (-20)/(21)\\

Hence the value of the expression is -20/21

answered
User Gregg Lind
by
7.5k points
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