Question

Find the term of each sequence.

32, 80, 200, ...5th term

Answer 1

t5 = 1250

Explanation:

Each term is derived by multiplying the previous term by 2.5

t2 = t1 * 2.5

t2 = 32 * 2.5

t2 = 80

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tn = a*b^(n - 1)

t3 = 32*2.5^2

t3 = 200

That's just to test the formula. It does work.

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t5 = 32*2.5^(5 -1)

t5 = 32*2.5^4

t5 = 1250