Answer:
 I₃ = I₀ 0.395
Step-by-step explanation:
Polarized light passing through a polarizer must comply with Malus's law 
 I = I₀ cos² θ 
 
Before starting, let's analyze the angle between the polarizers, the second has the same angle with the first and the third, so it is at the midpoint 
 θ₂ = 39/2 = 19.5 
 
now let's analyze the light that passes through each polarizer, as the incident is unpolarized through the first polarizer half the intensity comes out 
 I₁ = I₀ / 2
 
the second polarizer comes out 
 I₂ = I₁ cos² 19.5 
 I₂ = I₀ / 2 cos² 19.5 
 
through the third polarized the intensity passes 
 I₃ = I₂ cos² 19.5 
 I₃ = (I₀ /2 cos² 19.5) cos² 19.5 
 
 I₃ = I₀ 0.395