Question

Tree diagram:

Emily has a box with 4 different colored tiles: one red, one green, one blue and one yellow. If he draws one of the pieces without looking, what is the probability of drawing the green before the red?

Answer 1

Answer:
`(1)/(12)`

Explanation:

Given: Emily has a box with 4 different colored tiles: one red, one green, one blue and one yellow.

We assume that repetition is not allowed

Total number of ways to draw two tiles =
`^4P_2=(4!)/((4-2)!)` [By permuattaions]

`=(4*3*2)/(2)=12`

Favourable outcome = First green then red (only one way)

So, the probability of drawing the green before the red
`=\frac{\text{favorable outcomes}}{\text{Total outcomes}}`

`=(1)/(12)`

hence, the required probability =
`(1)/(12)`