Question

3/x-2, i'm confused as to what the horizontal asymptote is. The resources I found online conclude that it has a horizontal asymptote of y=0. I know that in order for a horizontal asymptote to be y=0, the denominator has to have a greater degree than the numerator. Im confused because doesn't the numerator have the same degree as the denominator (degree of 1)?

Answer 1

y = 0

Explanation:

Given

f(x) =
`(3)/(x-2)`

The degree of the numerator is zero 0 ( 3
`x^(0)` )

The degree of the denominator is 1

Since the degree of denominator > degree of numerator.

Then there is a horizontal asymptote at y = 0