Question

Find the 9th term geometric sequence 1,1/2,1/2^2

Answer 1

Answer:
`t_9=(1)/(2^8)`

Explanation:

`t_n=t_1* r^(n-1)\\\\Given: t_1=1,\quad r=(1)/(2)\\\\\\t_9=1*\bigg((1)/(2)\bigg)^(9-1)\\\\\\.\quad =\large\boxed{(1)/(2^8)}`