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If f(x) = √(x²-9) , then Domain of f = __________ (a) (-∞,-3)∪(3,∞) (b) (-∞,-3]∪ [3,∞) (c) (-∞,∞) (d) [-3,3]

If f(x) = √(x²-9) , then Domain of f = __________ (a) (-∞,-3)∪(3,∞) (b) (-∞,-3]∪ [3,∞) (c) (-∞,∞) (d) [-3,3]
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if f(x) = √(x²-9) , then Domain of f = __________ (a) (-∞,-3)∪(3,∞) (b) (-∞,-3]∪ [3,∞) (c) (-∞,∞) (d) [-3,3]

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User Antalkerekes
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1 Answer

3 votes

Answer:

domain is:(-∞,-3]∪ [3,∞)

Explanation:

f(x)=√(x²-9)

f(x)=√(x-3)(x+3)

domain is:(-∞,-3]∪ [3,∞)

if f(x) = √(x²-9) , then Domain of f = __________ (a) (-∞,-3)∪(3,∞) (b) (-∞,-3]∪ [3,∞) (c-example-1
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User Pieter Meiresone
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