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A 25.0-mL sample of 0.100M Ba(OH)2(aq) is titrated with 0.125 M HCl(aq). How many milliliters of the titrant will be needed to reach the equivalence point?

A 25.0-mL sample of 0.100M Ba(OH)2(aq) is titrated with 0.125 M HCl(aq). How many milliliters of the titrant will be needed to reach the equivalence point?
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A 25.0-mL sample of 0.100M Ba(OH)2(aq) is titrated with 0.125 M HCl(aq).

How many milliliters of the titrant will be needed to reach the equivalence point?

asked
User Alex Amato
by
8.3k points

1 Answer

0 votes

Answer:

20.0

Step-by-step explanation:

NaOH = (25.0) (0.100m) \ 0.125M = 20.0mL

answered
User Vijay Chavda
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8.3k points
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