Question

A vertically polarized light wave of intensity 1000 mW/m2 is coming toward you, out of the screen. After passing through this polarizing filter, the wave's intensity is

Answer 1

The intensity is
`I = 500 mW/m^2`

Step-by-step explanation:

From the question we are told that

The intensity of the unpolarized light is
`I_o = 1000 \ m W /m^2 = 1000 *10^(-3) \ W/m^2`

Generally the intensity of the light emerging from the polarizer is mathematically represented as

`I = (I_o)/(2)`

substituting values

`I = (1000 *10^(-3))/(2)`

`I = 500 *10^(-3) W/m^2`

`I = 500 mW/m^2`