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2 votes
On January 1, an investment account is worth 300,000. M months later, the value has increased to 315,000 and 15,000 is withdrawn. 2M months prior to the end of the year, the account is again worth 315,000 and 15,000 is withdrawn. On December 31, the account is worth 315,000. The annual effective yield rate, using the dollar-weighted method, is 16%. Calculate M.

asked
User Dora
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8.3k points

1 Answer

5 votes

Answer:

M = 3

Step-by-step explanation:

The first withdrawal takes place 1 - M/12 months until the end of the year. The second withdrawal takes place 2M/12 months before the end of the year.

$315,000 = ($300,000 x 1.16) - {$15,000 x [1 + 0.16(1 - M/12)]} - {$15,000 x [1 + 0.16(2M/12)]}

$315,000 = $348,000 - [$15,000 x (1.16 - 0.16M/12)] - [$15,000 x (1 + 0.32M/12)]

$315,000 = $348,000 - $17,400+ 200M - $15,000 - 400M

$315,000 = $315,600 - 200M

200M = $315,600 - $315,000 = $600

M = 600 / 200 = 3

answered
User Svural
by
10.0k points

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