Question

The net of a solid is shown below:

Net of a square pyramid showing 4 triangles and the square base. The square base has side lengths of 3 inches. The height of each triangle attached to the square is 6 inches. The base of the triangle is the side of the square.

What is the surface area of the solid?

18 square inches
27 square inches
36 square inches
45 square inches

Answer 1

The answer is 45 inches².

Explanation:

First, you have to find the area of each triangle:

`area = (1)/(2) * base * height`

`let \: base = 3 \\ let \: height = 6`

`area = (1)/(2) * 3 * 6`

`area = (1)/(2) * 18`

`area = 9 \: \: {inches}^(2)`

Assuming that the formula for surface area of pyramid is Surface area = base area(area of square) × 4(area of triangle):

`base \: area = 3 * 3 = 9`

`area \: of \: triangle = 9`

`s.a = 9 + 4(9)`

`s.a = 9 + 36`

`s.a = 45 \: \: {inches}^(2)`