Question

What is the vertex of f(x)=-3(x+2)^2+4

Answer 1

vertex(-2,4)

Explanation:

f(x)=-3(x+2)^2+4

f(x)=-3(x²+4x+4)+4

f(x)=-3x²-12x-12+4

= -3x²-12x-8

v(h,k)

h=-b/2a=-(12/-6)==2

substitute for x=-2

k=-3(2)²-12(-2)-8=-12+24-8=4