Question

Find the inverse of the one-to-one function f(x)=-8x+8

Answer 1

`\huge\boxed{f^(-1)(x)=-(1)/(8)x+1}`

Explanation:

`f(x)=-8x+8\to y=-8x+8`

change x with y

`x=-8y+8`

solve for y

`-8y+8=x` subtract 8 from both sides

`-8y+8-8=x-8`

`-8y=x-8[\tex]        <em>divide both sides by (-8)</em></p><p>[tex](-8y)/(-8)=(x)/(-8)-(8)/(-8)\\\\y=-(1)/(8)x+1`