asked 158k views
1 vote
A triangle has three sides of the following side lengths: 7, 10, and x^2. What are all of the positive integer values of x such that the triangle exists? Separate your answers using commas and express them in increasing order.

asked
User Sadhu
by
8.1k points

1 Answer

5 votes

Answer:

x = {2,3,4} (if x can only be positive whole numbers)

Explanation:

For a triangle exists, the side lengths of the triangle must be such that the sum of the two shorter sides must be greater than the third side.

This also is equivalent to any two sides must have a sum greater than the third side.

So

7+10 > x^2, => x^2 < 17 => x < sqrt(17) (maximum)

7+x^2 > 10, => x^2 >3 => x > sqrt(3)

Therefore

sqrt(3) < x < sqrt(17)

If x must be an integer,

2< x < 4, or x = {2,3,4}

answered
User Islam
by
8.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.