Question

Onyango is now three times as old as his daughter and four times as old as his son. Eight years from now, Onyango's age will be twelve years more than the sum of the ages of his son and daughter. Find their present ages.

Answer 1

Onyango is 48, his daughter is 16 and his son is 12

Explanation:

Let's call Onyango's age x, therefore his daughter and son's ages are 1/3 x and 1/4 x respectively. We can write:

x + 8 = 12 + (1/3x + 8 + 1/4x + 8)

x + 8 = 7/12x + 28

5/12x = 20

x = 48 → 1/3x = 48 / 3 = 16, 1/4x = 48 / 4 = 12