$\sf 3x^2-5x-7=0\\\\x = \frac{-b\±\sqrt{b^(2)-4ac } }{2a} \\\\\\x = \frac{-(-5)\±\sqrt{(-5)^(2)-4 ~*~3~*~ (-7) } }{2~*~ (-5)} \\\\\\\boxed{\sf x = (5\±√(109) )/(-10)}$

LeonardBlunderbuss answered Jul 3, 2023

by LeonardBlunderbuss

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Solve the quadractic equation 3x^2-5x-7=0

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